(x^2+2xy+y^2)(x+1)=

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Solution for (x^2+2xy+y^2)(x+1)= equation: 


Simplifying
(x2 + 2xy + y2)(x + 1) = 0

Reorder the terms:
(2xy + x2 + y2)(x + 1) = 0

Reorder the terms:
(2xy + x2 + y2)(1 + x) = 0

Multiply (2xy + x2 + y2) * (1 + x)
(2xy * (1 + x) + x2(1 + x) + y2(1 + x)) = 0
((1 * 2xy + x * 2xy) + x2(1 + x) + y2(1 + x)) = 0
((2xy + 2x2y) + x2(1 + x) + y2(1 + x)) = 0
(2xy + 2x2y + (1 * x2 + x * x2) + y2(1 + x)) = 0
(2xy + 2x2y + (1x2 + x3) + y2(1 + x)) = 0
(2xy + 2x2y + 1x2 + x3 + (1 * y2 + x * y2)) = 0

Reorder the terms:
(2xy + 2x2y + 1x2 + x3 + (xy2 + 1y2)) = 0
(2xy + 2x2y + 1x2 + x3 + (xy2 + 1y2)) = 0

Reorder the terms:
(2xy + xy2 + 1x2 + 2x2y + x3 + 1y2) = 0
(2xy + xy2 + 1x2 + 2x2y + x3 + 1y2) = 0

Solving
2xy + xy2 + 1x2 + 2x2y + x3 + 1y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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